Question 259216
Let the numbers be A and B.
1.{{{B=2A+1}}}
2.{{{3A=B+6}}}
Substitute eq. 1 into eq. 2,
2.{{{3A=B+6}}}
{{{3A=(2A+1)+6}}}
{{{3A=2A+7}}}
{{{A=7}}}
Then use eq. 1 to solve for B,
{{{B=2A+1}}}
{{{B=2(7)+1=15}}}