Question 259180
The domain is all x except for x which make the denominator zero since division by zero is not allowed. 
{{{2x^2-3x-5=0}}}
{{{(2x-5)(x+1)=0}}}
Two solutions:
{{{ 2x-5=0}}}
{{{2x=5}}}
{{{x=5/2}}}
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{{{ x+1=0}}}
{{{x=-1}}}
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({{{-infinity}}},{{{-1}}})U({{{-1}}},{{{5/2}}})U({{{5/2}}},{{{infinity}}})
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{{{ graph( 300, 300, -5, 5, -2, 2, (3x-7)/(2x^2-3x-5)) }}}