Question 259120
Vertex form:
{{{y=a(x-h)^2+k}}}
{{{y=a(x-3)^2+2}}}
When x=0, y=0
{{{0=a(-3)^2+2}}}
{{{a=-2/9}}}
{{{y=-(2/9)(x-3)^2+2}}}
{{{ graph( 300,300, -5, 5, -5, 5, -(2/9)(x-3)^2+2) }}}