Question 259141
Please show me how to use combinations to solve: How many ways can a committee of 6 men and 8 women be selected from a group of 12 men and 20 women? 

I know I need the formula N!/(n!(N-n)!)  but I don't know how to combine men and women. 
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Remember: "AND" means "MULTIPLY" and "OR" means "ADD".

This problem is selecting the men AND the women so you MULTIPLY.

You can select the 6 men any of {{{12!/(6!6!)}}} = 924 ways. 

You can select the 8 women any of {{{20!/(8!12!)}}} = 125970 ways.
 
Get each of those and multiply them.  Answer:  116396280 ways.

Edwin</pre>