Question 32578
x = sqrt(6-x)
Take squares on both sides:
x^2 = 6-x
=> x^2+x-6 = 0
=> x^2+3x-2x-6 = 0
=> x(x+3)-2(x+3) = 0
=> (x+3)(x-2) = 0
=> Either (x+3) = 0 or (x-2) = 0
=> x=-3 or x=2