Question 32579
Solution for x will be in terms of h(x).
h(x)= 4^(2x-1)
Take log on both sides
log h(x) = log [4^(2x-1)]
=> log h(x) = (2x-1) log 4
=> (2x-1) = [log h(x)]/[2 log 2] .... (log 4 = log 2^2 = 2 log 2)
=> 2x = 1 + [log h(x)]/[2 log 2]
=> x = (1/2)[1 + {log h(x)/(2 log 2)}]