Question 259024
Here is the original problem
{{{3a^2+a-14}}}
there are several ways to factor. The basic idea is to get (ax+b)(cx+d)
--
step 1 - multiply 3 and 14 to get 42.
we want 2 factors of 42 that add to 1, but are different signs.
we get 7 + (-6)
--
step 2 - replace 1a with 7a - 6a like this
{{{3a^2 - 6a + 7a - 14}}}
step 3 - group the first pair and last pair and find the GCF of each like this
{{{(3a^2 - 6a) + (7a - 42)}}}
finding GCF's we get
{{{3a(a - 2) + 7(a - 2)}}}
notice the parenthesis are the same; this is what we want to happen.
step 4 - find another GCF as
{{{(a-2)(3a+7)}}}
and you have factored.