Question 32495
h(t)= -16t^2+35t+1250
you have to find the time when h = 0 - that's when it hits the ground.
-16t^2+35t+1250 = 0
16tē - 35 - 1250 = 0
using the quadratic formula, {{{t = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}, we get
{{{t = (35 +- sqrt( (-35)^2-4*(16)*(-1250) ))/(2*16) }}}
{{{t = (35 +- sqrt( 1225 + 80000) )/(32) }}}
{{{t = (35 +- 285 )/32 }}}
{{{t = 320/32}}}, {{{t = -250/32 }}}
{{{t=10}}}, {{{t=-7.8125}}}
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