Question 258916
find two consecutive odd integers whose product is 195
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1st: 2x+1
2nd: 2x+3
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Equation:
(2x+1)(2x+3) = 195
4x^2 +8x + 3 = 195
4x^2 + 8x - 192 = 0
4(x^2 + 2x - 48)
(x-6)(x+8) = 0
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Positive solution:
x = 6
1st: 2x+1 = 13
2nd: 2x+3 = 15
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Negative solution:
x = -8
1st: 2x+1 = -15
2nd: 2x+3 = -13
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Cheers,
Stan H.
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