Question 258804
The first integer has to be a square so that the square root is an integer.
{{{ N=1}}} , {{{sqrt(N)=1}}}, {{{(2)(3)=6}}}, {{{1+6=7 }}}
{{{N=4}}}, {{{sqrt(N)=2}}}, {{{(5)(6)=30}}}, {{{4+30=34}}}
{{{N=9}}}, {{{sqrt(N)=3}}}, {{{(10)(11)=110}}}, {{{9+110=119}}}
We're already over 46 and this function will only increase.
No solution.