Question 258779
Again no idea what you mean by "two order system"
j=m+5 and 
2(j+10)-(m+10)=35 and 
j+10=2m
j=20
m=15


We can solve by just using the first and last equations.
j=m+5
j+10=2m
m+5+10=2m
m+15=2m
15=m
j=20
Just for fun lets check using the unused equation
2(j+10)-(m+10)=35 
2(30)-25=35
60-25=35
35=35
ok