Question 258742
Surface area for the can is the sum of the circular top and bottom and the rolled out portion of the side, which rolls out to a rectangle.
{{{SA1=pi*R^2+pi*R^2+2*pi*R*H=2*pi*(R^2+R*H)}}}
{{{SA2=pi*R^2+pi*R^2+2*pi*R*h=2*pi*(R^2+R*h)}}}
You also know that 
{{{SA1=4*SA2}}}
{{{2*pi*(R^2+R*H)=8*pi*(R^2+R*h)}}}
{{{R^2+R*H=4R^2+4(R*h))}}}
{{{R*H=3R^2+4(R*h))}}}
{{{H-4*h=3R}}}
{{{R=(1/3)(H-4*h)}}}
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I don't get the same answer. Are you sure it's a 2 dividing the entire height term on the right hand side??