Question 258778
1.{{{2x-4y=6}}}
2.{{{2x+y=1 }}}
Since both have a "2x" term solve eq. 1 for 2x and substitute into eq. 2,
1.{{{2x-4y=6}}}
{{{2x=4y+6}}}
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2.{{{2x+y=1 }}}
{{{(4y+6)+y=1 }}}
{{{5y+6=1 }}}
{{{5y=-5 }}}
{{{y=-1}}}
Then from above,
{{{2x=4y+6}}}
{{{2x=4(-1)+6}}}
{{{2x=-4+6}}}
{{{2x=2}}}
{{{x=1}}}
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(x,y)=(1,-1)