Question 32494
x=y^2 + 14y + 20
This is a parabola having directrix parallel to the y-axis (sidewise, opening on the right side).
x = y^2+14y+20
=> x = y^2 + 14y + 49 - 29
=> x = (y+7)^2 - 29
The vertex of the parabola is at (-29, -7).
The directrix of the parabola is at y = -14
Let me know if you need any additional information.