Question 258737
From the Pythagorean theorem,
1.{{{a^2=b^2+c^2}}}
From the area of a triangle,
{{{A=(1/2)bh}}} where b is the base, h is the height.
For a right triangle, b and h are the legs, in this case, b and c.
{{{A=(1/2)bc=a^2+b^2-c^2}}}
{{{(1/2)bc=a^2+b^2-c^2}}}
Use eq. 1 and substitute,
{{{(1/2)bc=(b^2+c^2)+b^2-c^2}}}
{{{(1/2)bc=2b^2}}}
{{{bc=4b^2}}}
{{{bc/b^2=4}}}
{{{c/b=4}}}