Question 258702
Let the numbers be A and B.
{{{A=60+B}}}
.
.
{{{A/B=4}}}
{{{A=4B}}}
Substitute this into the first equation and solve for B.
{{{A=60+B}}}
{{{4B=60+B}}}
{{{3B=60}}}
{{{B=20}}}
Then,
{{{A=60+B=60+20=80}}}
The two numbers are 20 and 80.