Question 258715
Use the first equation to solve for y.
{{{2x-y=8}}}
{{{y=2x-8}}}
Now substitute into eq.2 and 3 for y.
{{{x-6y-z=0 }}}
{{{x-6(2x-8)-z=0}}}
{{{x-12x+48-z=0}}}
{{{-11x-z=-48}}}
{{{11x+z=48}}}
.
.
.
I assume it should be "=24"?
{{{-6x+3y-9z=24 }}}
{{{-6x+3(2x-8)-9z=24}}}
{{{-6x+6x-24-9z=24}}}
{{{-9z=48}}}
{{{highlight( z=-16/3)}}}
Now go back and substitute to find x and then y.
{{{11x+z=48}}}
{{{11x-(16/3)=48}}}
{{{33x-16=144}}}
{{{33x=160}}}
{{{highlight( x=160/33)}}}
and then
{{{y=2x-8}}}
{{{y=2(160/33)-8}}}
{{{y=320/33-264/33}}}
{{{highlight( y=56/33)}}}