Question 258754
{{{x^2-5x+5=0 }}}
Use the quadratic formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (-(-5) +- sqrt( (-5)^2-4*1*5 ))/(2*1) }}} 
{{{x = (5 +- sqrt( 25-20 ))/(2) }}}
{{{x = (5 +- sqrt( 5))/(2) }}}
or approximately,
{{{x=3.618}}} and {{{x=1.382}}}
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{{{ graph( 300, 300, -1, 5, -3, 3,  x^2-5x+5) }}}