Question 258562
Let X, X+1, and X+2 be the three consecutive integers
From above we get
{{{3*(x+x+1+x+2) = 72}}}
dividing by 3, we get
{{{3x+3 = 24}}}
subtracting 3, we get
{{{3x = 21}}}
so,
{{{x = 7}}}
and the three integers are
(7, 8, 9)