Question 258559
Lets start with the Pythagorean theorem as
{{{a^2 + b^2 = c^2}}}
from above, we get
{{{sqrt(16)^2 + sqrt(19)^2 = c^2}}}
{{{16 + 19 = c^2}}}
{{{35 = c^2}}}
{{{c = sqrt(35)}}}