Question 258205
This is the solution to an intersection of a circle and a line.
1.{{{x^2+y^2=169}}}
2.{{{5x-12y=0}}}
From eq. 2,
{{{5x=12y}}}
{{{25x^2=144y^2}}}
{{{x^2=(144/25)y^2}}}}
Substitute into eq. 1,
1.{{{x^2+y^2=169}}}
{{{(144/25)y^2+y^2=169}}}
{{{144y^2+25y^2=4225}}}
{{{169y^2=4225}}}
{{{y^2=4225/169=25}}}
{{{y=0 +- 5}}}
When {{{y=5}}},
{{{5x=12y}}}
{{{x=12}}}
When {{{y=-5}}},
{{{x=-12}}}
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.
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{{{drawing( 300, 300, -15, 15, -15, 15,grid( 1 ),circle( 12, 5, .5), circle( -12, -5, .5 ),graph( 300, 300, -15, 15, -15, 15, (5/12)x, -sqrt(169-x^2),sqrt(169-x^2))) }}}