Question 258302
Factor completely: 64x^3+343
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It's the sum of 2 cubes.
{{{a^3 + b^3 = (a+b)*(a^2 - ab + b^2)}}}
Sub 4x for a, and 7 for b
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{{{64x^3 + 343 = (4x+7)*(16x^2 - 28x + 49)}}}
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The difference of 2 cubes is similar:
{{{a^3-b^3 = (a-b)*(a^2 + ab + b^2)}}}
The difference of any 2 odd powers is also similar.