Question 258231
Solve for x:
{{{5x^3+26x^2+5x = 0}}} First, factor an x.
{{{x(5x^2+26x+5) = 0}}} Apply the zero product rule.
{{{highlight(x = 0)}}} or... 
{{{5x^2+26x+5 = 0}}} Use the quadratic formula to solve for x: {{{x = (-b+-sqrt(b^2-4ac))/2a}}} Substitute a = 5, b = 26, and c = 5.
{{{x = (-26+-sqrt(26^2-4(5)(5)))/(2*5)}}}
{{{x = (-26+-sqrt(676-100))/10}}}
{{{x = (-26+-sqrt(576)/10)}}}
{{{x = -2.6+2.4}}} or {{{x = -2.6-2.4}}}
{{{highlight(x = -0.2)}}} or {{{highlight(x = -5)}}}