Question 258125
Let x, x+1, and x+2 be the three consecutive integers. WE have
(i) {{{x + x + 1 +  x + 2 = 66}}}
combining like terms we get
(ii) {{{3x+3 = 66}}
subtracting 3 we get
(iii) {{{3x = 63}}}
dividing by 3 we get
(iv) {{{x = 21}}}
S our three numbers are:
 21, 22, 23