Question 258036
We are given
(i) {{{y=(2/3)x-25/3}}}
standard form requires two things
(1) no fractions
(2) x and y on the same side
--
step 1 - multiply (i) by 3 to get
(ii) {{{3y = 2x - 25}}}
step 2 - subtract 2x to get
{{{-2x + 3y = - 25}}}
at this point some teacher require positive x's, sop we could write
{{{2x  - 3y = 25}}}