Question 257813
The original problem is given as:
{{{((3x-3) / (2x-5)^2) / ((2x^2+3x-5) / (4x^2-25))}}}
step 1 - multiply by the reciprocal gets us
{{{((3x-3)/(2x-5)^2)* ((4x^2-25)/(2x^2+3x-5))}}}
step 2 - factor to get
{{{(3*(x-1)/(2x-5)^2)*((2x-5)*(2x+5)/(2x+5)(x-1))}}}
step 3 - cancel to get
 {{{3/(2x-5)}}}