Question 257755
Don't let the powers in the numerator & denominator confuse you.
Break the fractions down into manageable fractions.
Start with the x terms:
(11x^3/9q^2)(81q^5/121x)
11x^3/121x Factor out the common value 11
x^3/11x Now subtract the power in the denominator from the power in the numerator.
x^3+x^-1=x^(3-1)=X^2
Thus we have x^2/11
Now for the q fraction
81q^5/9q^2 Factor out the value 9
9q^5/q^2 Now again subtract the power of the denominator from the power in the numerator.
q^5+q^(-2)=q^(5-2)=q^3 
Thus we have 9q^3
The answer is:
[9q^3*x^2/11]