Question 257750
The tens digit of a two digit number is 3 more than the units digit. The number is 8 more than six times the sum of the digits. Find the number?

Let x be the tens digit and y the ones digit. Then the numbr itself is equal to 10*x + y.

We have then:

1.) x = y + 3 and
2.) 10*x + y = 6*(x+y) + 8

Substitute y + 3 from 1.) for x in 2.) and solve 2.) for y. Once you have the value of y, calculate x = y + 3 (from 1.)