Question 257726
one way with q 1q
2 dimes and a nickel 
2 dimes and 5 pennies
1 dime 3 n 
1d 2n 5p
25=
1q=1
+(2d+5)  1n or 5p 2
+(1d+15) n+10p 2n+5p 2
+ 5n 1
 +(4n+5) 1
+(2n+15) d+5p 1
+25p 1
+20p+5 1
+15p+10 +d +2n 2
+10p+15 d+n 1
+(5p+20) 2d 1d+2n 2

15 if various combos of individual pennies, nickels and dimes are counted as 1
Not interested in counting if each penny is counted as a separate way.
Then the 25 pennies become 25!
 
 So there is probably some duplication here .