Question 257637
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The other tutor misread and gave you the least rather than the 
largest number of nickels.


.05n + .10d = 15.25
  
   5n + 10d = 1525

divide through by 5

     n + 2d = 305
         2d = 305 - n  
   
          d > n
         2d > 2n

    305 - n > 2n
        305 > 3n
{{{101&2/3}}} > n

101 would be the largest number of nickels ignoring the 
requirement that we have an odd number of dimes.

2d = 305 - n
2d = 305 - 101
2d = 204
 d = 102

The answer would be 101 nickels and 102 dimes if we could
have an even number of dimes. But since we can't have an 
even number of dimes, we have to put in one more dime, 
and thus take away 2 nickels and get

99 nickels and 103 dimes. 

Edwin</pre>