Question 257485
Let the original number be expressed as
{{{10t + u}}}
When you reverse the digits, you get
{{{10u + t}}}
Now the quotient = 2.08 as
{{{(10t+u)/(10u+t) = 2.08}}}
We also know that t + u = 7, so t = 7-u. We get
{{{(10*(7-u+u))/(10u+7-u) = 2.08}}}
This gives us
{{{(70-9u)/(9u+7) = 2.08}}}
cross multiplying, we get
{{{70-9u = 18.72u + 14.56}}}
solving for u, we get
{{{55.44 = 27.72u}}}
{{{u = 2}}}
{{{t = 5}}}
original number is 52
reversed number is 25.
quotient is 2.08