Question 257434
n = 3^x + 3^x + 3^x and  n^2 = A^(x+1)
n = 3^(x+1)and  n^2 = A^(x+1)
n^2=(3^(x+1))^2
A^(x+1)=(3^(x+1))^2

A^(x+1)=9^(x+1)
A=9