Question 257422
The sum of two consecutive integers is 19 less than their product. Find the integers
.
Let x = first of two consecutive integers
then
x+1 = second of two consecutive integers
.
x + x+1 = x(x+1) - 19
2x+1 = x^2 + x - 19
1 = x^2 - x - 19
0 = x^2 - x - 20
0 = (x-5)(x+4)
x = {-4, 5}
.
Two possible answers
5 and 6
.
Or,
-4 and -3