Question 257380
Eva is 6 years older than his brother, Elvin. In 4 years, Eva will be 26 more than one-half of Elvin's age. How old are they now?


Let Elvin's age be {{{E[l]}}}


Then Eva's age is {{{E[l] + 6}}}


In 4 year's time, Eva will be {{{E[l] + 6 + 4}}}, and Elvin will be {{{E[l] + 4}}}


Since in 4 year's time, Eva will be 26 more than one-half of Elvin's age, then we'll have: 


{{{E[l] + 6 + 4 = (1/2)*(E[l] + 4) + 26}}}


{{{E[l] + 10 = (E[l] + 4)/2 + 26}}}


{{{2E[l] + 20 = E[l] + 4 + 52}}} ------ Multiplying both sides of equation by LCD, 2


{{{E[l] = 36}}}


Therefore, {{{E[l]}}}, or Elvin's age is {{{highlight_green(36)}}} and Eva's age is {{{highlight_green(42)}}} (36 + 6)