Question 257136
First find the slope.
{{{m=(y2-y1)/(x2-x1)}}}
{{{m=(6-3)/(-4-(-2))}}}
{{{m=3/(-2)=-(3/2)}}}
Now usethe point-slope form of a line with either point (xp, yp) and slope m:
{{{y-yp=m(x-xp)}}}
{{{y-3=-(3/2)(x-(-2))}}}
{{{y-3=-(3/2)(x+2)}}}
{{{y-3=-(3/2)x-3)}}}
{{{y=-(3/2)x)}}}
{{{drawing( 300, 300, -7,7,-7,7,grid( 1 ),circle( -2, 3, .3 ),circle( -4, 6, .3), graph( 300, 300, -7,7,-7,7, -(3/2)x) )}}}