Question 257273
x^2-2x-3=0

(x-3)(x+1)=0 (using foil , first outer inner last)
x^2+x-3x-3=0 (you get same equation)

x=3 or x=-1

using quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
where a=1, b=-2, c=-3

*[invoke quadratic "x", 1, -2, -3]