Question 257261
Let x, x+2, and x+4 be the 3 consecutive odd integers.
From above, we have:
(i) {{{(x)(x+2) = (x+4)^2 - 34}}}
by foiling, we get
(ii) {{{x^2 + 2x = x^2  + 8x + 16 - 34}}}
simplifying we get
(iii) {{{x^2 + 2x = x^2 + 8x - 18}}}
setting = 0, we get
(iv) {{{6x - 18 = 0}}}
solving for x, we get
 {{{x = 3}}}
If x = 3, the 3 consecutive odd integers are {3, 5, 7}