Question 257212
Find the largest of four consecutive odd integers such that the sum of the first and the fourth is 27 less than three times the first integer.

Let x be the smallest of the integers. Then the other three are x+2, x+4 and x+6.

We know then that:

x + (x+6) = 3*x - 27

Solving for x:

2*x + 6 = 3*x - 27
x = 33

The larger integer then is x + 6 = 39.