Question 257206
{{{sqrt(4x^2-64)=6}}}
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Squaring both sides we get:
{{{4x^2-64= 36}}}
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{{{4x^2-64-36 = 0}}}
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{{{4x^2-100 = 0}}}
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Notice the left is a "difference of squares":
{{{(2x)^2-(10)^2 = 0}}}
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Which can be factored as:
{{{(2x-10)(2x+10) = 0}}}
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Setting each term (on the left) to zero we get:
x = {-5,5}