Question 257092
We have the following:
{{{(t+k)/2}}} ={{{(t^2-t-7)/(2+2t) }}}
step 1 - cross multiply to get
{{{(t+k)(2+2t) = (t^2-t-7)*(2)}}}
step 2 - distribute to get
{{{2t^2 + 2t + 2k + 2kt = 2t^2 - 2t - 14}}}
simplify and get
{{{4t + 2k + 2kt + 14 = 0}}}
pulling out the GCF of t, we get
{{{t(4+2k) = -2k - 14}}}
dividing, we get
{{{t = (-2k-14)/(4+2k)}}}
simplifying, we get
{{{t = (-k-7)/(2+k)}}}