Question 257039
If the first number is 43 less than twice the second number, let:
2x - 43 = the first number
x = the second number


Since they add up to 50, the equation becomes: {{{x+2x-43=50}}}
Now solve for x to find the second number, then deduct 43 to find the other number.


{{{3x=50+43}}}
{{{3x=93}}}
{{{x=93/3}}}
{{{x=31}}}


I'll let you find the other number.