Question 257092
 (t+k)/2=(t^2-t-7)/(2+2t) 
solve for t.
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Multiply both sides by 2 to get:
(t+k) = (t^2-t-7)/(1+t)
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Multiply both sides by 1+t to get:
t + t^2 + k + kt = t^2-t-7
2t+kt = -(k+7)
t(2+k) = -(k+7)
t = -(k+7)/(k+2)
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Cheers,
Stan H.