Question 257080
We can solve the following
{{{x^2+3x-5=0 }}}
by completing th square as

{{{(x+1.5)^2 -7.25=0}}}
and solving for x we get
{{{(x+1.5)^2 = 7.25}}}
{{{x+1.5 = +-sqrt(7.25)}}}
{{{x = -1.5 +- sqrt(7.25)}}}
x ~ 1.193
x ~ -4.193