Question 257063
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You have a perfectly good beginning.  Now all that you need to do is a little substitution.


Since *[tex \Large o\ =\ f\ +\ 60], we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f\ +\ \left(f\ +\ 60\right)\ +\ j\ +\ e\ =\ 1424]


and following the same logic, with the other two equations we can end up with:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f\ +\ \left(f\ +\ 60\right)\ +\ \left(2f\ -\ 50\right)\ +\ \left(3f\right)\ =\ 1424]


Now all you need to do is collect like terms and solve for *[tex \Large f].


You then need to calculate the size of the other three classes and see if they sum to 1424 in order to check your work.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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