Question 256991
We really have 2 coordinates here: (1,6) and (0,0).
step 1 - find the slope which is
{{{ m = (y2-y1)/(x2-x1)}}}
{{{m = (0-6)/(0-1)}}}
{{{m = 6}}}
step 2 - put the slope and point into 
{{{y = mx + b}}}
{{{0 = 0*6 + b}}}
{{{b = 0}}}
So we get
 y = 6x + 0