Question 256957
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Let *[tex \Large s] represent the measure of the side of the square.  Then:


Length of rectangle: *[tex \Large 2s\,-\,4]


Width of rectangle: *[tex \Large s\,-\,6]


The perimeter of a square is 4 times the measure of a side.  The perimeter of a rectangle is 2 times the measure of the length plus 2 times the measure of the width.  Further, the two perimeters are equal, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2\left(2s\,-\,4\right)\ +\ 2\left(s\,-\,6\right)\ =\ 4s]


Solve for *[tex \Large s], then multiply by 4 to give the perimeter of the square which is equal to the perimeter of the rectangle.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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