Question 256885
Let's start by naming variables.  Let's call the length L and the width W.  Then the first sentence tell us that:

L = 2W - 2

Remember that the perimeter of a rectangle is P = 2L + 2W.  So the second sentence tells us:

2L + 2W = 32

Now, in order to solve these two equations, notice that we can use the first equation to replace L with 2W - 2.  This gives us:

2(2W - 2) + 2W = 32
4W - 4 + 2W = 32
6W - 4 = 32
6W = 36
W = 6

So the width is 6 cm.  To finish the problem, we need to find the length, so let's substitute 6 in for W in the first equation:

L = 2(6) - 2
L = 12 - 2
L = 10

So the dimensions of the rectangle are 10 cm by 6 cm.