Question 256872
Let x be the integer. We get
{{{x + x^2 = 30}}}
rewriting, we get
{{{x^2 + x = 30}}}
setting equal to 0, we get
{{{x^2+x-30=0}}}
factoring, we get
{{{(x-5)(x+6)=0}}}
solving each parenthesis, we get
x = 5 and x = -6; choice (d)