Question 256861
Here is the question:
{{{Log_2(x) + log_2(x+2) = log_2(x+6)}}}
since all are base 2 and we see + on the left, we can rewrite as
{{{log_2(x)(x+2) = log_2(x+6)}}}
now cross out the log_2 and solve for x as
{{{x(x+2) = x+6}}}
{{{x^2 + 2x - x - 6 = 0}}}
{{{x^2 + x - 6 = 0}}}
{{{(x+3)(x-2)=0}}}
So, x = -3 or x = 2.
If x = -3, then there would be no solution.
So, x = 2.