Question 256805
(NOTE: A different solution from another tutor starts off correctly but it has an error.)<br>
As stated in the other solution, we do want to find where
1 - cos(2x) = 0
or
1 = cos(2x)<br>
The error comes next. The cos function is 1 for 0 radians, not {{{pi/2}}}. So:
{{{2x = 0 + 2pi*n}}} where n is any integer.
For x, we divide both sides by 2:
{{{x = 0/2 + 2pi*n/2}}} where n is any integer.
which simplifies to:
{{{x = 0 + pi*n}}} where n is any integer.